Integration foundations

Integrals and the Fundamental Theorem of Calculus

Connect antiderivatives with accumulation and evaluate definite integrals efficiently using the Fundamental Theorem of Calculus.

How this page is maintained

Written for learners, checked against the sources below, and reviewed every year. Last reviewed July 22, 2026.

Short answer

The Fundamental Theorem of Calculus links area accumulation to antiderivatives: if F' = f, then integral from a to b of f(x) dx equals F(b) - F(a).

  • Definite integrals represent signed accumulation.
  • FTC turns many definite integrals into endpoint evaluation.
  • Keep bounds and antiderivative parentheses clear.

Understand accumulation and sign

A definite integral accumulates net change. Area above the axis contributes positively, and area below contributes negatively.

This signed interpretation explains why a large geometric area can still yield a small net integral.

Use antiderivatives with bounds

Find an antiderivative F(x), then compute F(b)-F(a). Keep exact values when possible before decimal approximation.

Indefinite integrals need +C, but definite integrals do not keep +C because constants cancel in subtraction.

  • Reverse bounds changes the sign of the integral.
  • Integral over zero-width interval is zero.
  • Linearity allows splitting complex sums into simpler terms.

Evaluate a polynomial definite integral

Compute integral from 1 to 3 of (2x + 1) dx.

  1. Find antiderivative: integral of (2x+1) is x^2 + x.
  2. Evaluate upper bound: F(3) = 9 + 3 = 12.
  3. Evaluate lower bound and subtract: F(1) = 1 + 1 = 2, so 12 - 2.
Result: The integral value is 10.

Common mistakes

  • Forgetting to subtract lower-bound value.
  • Adding +C to a definite integral result.
  • Dropping parentheses around F(b)-F(a).
  • Confusing geometric area with signed integral value.

Try one

If F' = f, how do you compute integral from a to b of f(x) dx?

Compute F(b) - F(a).

Sources

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