Solution sets

Linear Inequalities

Solve and graph linear inequalities in one or two variables, reverse the symbol after negative division, and test points to confirm the region.

How this page is maintained

Written for learners, checked against the sources below, and reviewed every year. Last reviewed July 22, 2026.

Short answer

Solve inequalities like equations with one key difference: if you multiply or divide by a negative number, reverse the inequality symbol. In two variables, graph the boundary line and shade the side that satisfies the inequality.

  • Reverse the inequality when multiplying or dividing by a negative.
  • Use open or closed boundary points based on strict or inclusive symbols.
  • Test a point to confirm the correct shaded region.

Keep track of symbol direction

Symbols < and > are strict, while <= and >= include boundary values. In one-variable graphs, strict inequalities use open circles and inclusive inequalities use closed circles.

Students often miss the sign flip after dividing by a negative. Write that step explicitly to reduce errors.

Graph in two variables

First graph the boundary equation, such as y = 2x - 1. Use a solid line for <= or >= and a dashed line for < or >. Then test a point not on the line, often (0, 0), to decide which side to shade.

  • Boundary line: equation version of the inequality.
  • Dashed line: boundary not included.
  • Solid line: boundary included.

Solve and graph a one-variable inequality

A discount applies when 3x - 7 <= 11, where x is quantity purchased.

  1. Add 7 to both sides: 3x <= 18.
  2. Divide by 3: x <= 6.
  3. Graph with a closed circle at 6 and shading to the left.
  4. Check x = 6 and x = 7 in the original inequality.
Result: All quantities up to and including 6 satisfy the condition.

Common mistakes

  • Forgetting to reverse the symbol after dividing by -1.
  • Using a solid boundary line for a strict inequality.
  • Shading without testing a point.
  • Treating one test point as proof for an algebraic manipulation error.

Try one

Solve -2x + 5 > 11.

Subtract 5: -2x > 6. Divide by -2 and reverse symbol: x < -3.

Sources

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